What is expand (-3x+y=7,)(3x+2x=2) ?

The solution to expand (-3x+y=7,)(3x+2x=2) is -15x^2=2

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expand (-3x+y=7,)(3x+2x=2)

expand

(- 3 x + y = 7,) (3 x + 2 x = 2)

- 15 x^{2} = 2

Solution steps

(- 3 x + y = 7,) (3 x + 2 x = 2)

= (- 3 x + 7 =, y) (3 x + 2 \cdot 2 = x)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = - 3 x, b = y = 7,, c = 3 x, d = 2 x = 2

(- 3 x) \cdot 3 x + (- 3 x) \cdot 2 x = 2 + y = 7, 3 x + y = 7, 2 x = 2

Apply minus-plus rules

+ (- a) = - a

- 3 \cdot 3 xx - 3 \cdot 2 xx = 2 + y = 7, 3 x + y = 7, 2 x = 2

Expand

- 3 \cdot 3 xx - 3 \cdot 2 xx : - 15 x^{2}

- 15 x^{2} = 2

\frac{d}{d t} ((r (t)) (2 t - 2))

- (x + 2 (ux))^{2} (x d u + u d x)

(168 - 6 π x) (π x)

30 c m^{2} \cdot (x - 5) e (x + 2)

\frac{( x + 1 )}{x ( x ^{2} + 1 )}

What is expand (-3x+y=7,)(3x+2x=2) ?
The solution to expand (-3x+y=7,)(3x+2x=2) is -15x^2=2