What is expand (4pi(3r^2+3hr+h^2))/3 ?

The solution to expand (4pi(3r^2+3hr+h^2))/3 is 4pir^2+4pihr+(4pih^2)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4pi(3r^2+3hr+h^2))/3

expand

\frac{4 π ( 3 r ^{2} + 3 h r + h ^{2} )}{3}

4 π r^{2} + 4 πh r + \frac{4 π h ^{2}}{3}

Solution steps

\frac{4 π ( 3 r ^{2} + 3 h r + h ^{2} )}{3}

Expand

4 π (3 r^{2} + 3 h r + h^{2}) : 12 π r^{2} + 12 πh r + 4 π h^{2}

= \frac{12 π r ^{2} + 12 πh r + 4 π h ^{2}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 π r ^{2} + 12 πh r + 4 π h ^{2}}{3} = \frac{12 π r ^{2}}{3} + \frac{12 πh r}{3} + \frac{4 π h ^{2}}{3}

= \frac{12 π r ^{2}}{3} + \frac{12 πh r}{3} + \frac{4 π h ^{2}}{3}

Divide the numbers:

\frac{12}{3} = 4

= 4 π r^{2} + 4 πh r + \frac{4 π h ^{2}}{3}

\frac{6 x}{( x - 3 ) ( x + 2 )}

\frac{( x - 1 ) ( x + 3 )}{x}

\frac{5 x ^{3} ( x + 1 )}{12}

- \frac{3}{( 5 x + 4 ) ^{9}}

A (6, 3) y B (- 2, - 3)

What is expand (4pi(3r^2+3hr+h^2))/3 ?
The solution to expand (4pi(3r^2+3hr+h^2))/3 is 4pir^2+4pihr+(4pih^2)/3