What is expand (1-e)(ba-bdac+dc) ?

The solution to expand (1-e)(ba-bdac+dc) is ba-bcda+dc-eba+ebcda-edc

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expand (1-e)(ba-bdac+dc)

expand

(1 - e) (ba - b d a c + d c)

ba - b c d a + d c - e ba + e b c d a - e d c

Solution steps

(1 - e) (ba - b d a c + d c)

= (1 - e) (ba - b c d a + d c)

Distribute parentheses

= 1 \cdot ba + 1 \cdot (- b d a c) + 1 \cdot d c + (- e) ba + (- e) (- b d a c) + (- e) d c

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 1 \cdot ba - 1 \cdot b c d a + 1 \cdot d c - e ba + e b c d a - e d c

Simplify

1 \cdot ba - 1 \cdot b c d a + 1 \cdot d c - e ba + e b c d a - e d c : ba - b c d a + d c - e ba + e b c d a - e d c

= ba - b c d a + d c - e ba + e b c d a - e d c

(6 + x)^{6}

t e (x^{3} y (t, x) - y (t, x) (t, x)^{2} = 3)

\frac{( x - 8 ) ( x - 2 )}{( x + 6 ) ( x - 3 )}

(1 + 0.024)^{X}

(5 x + (- 9) y = - 5) (0)

What is expand (1-e)(ba-bdac+dc) ?
The solution to expand (1-e)(ba-bdac+dc) is ba-bcda+dc-eba+ebcda-edc