What is the answer to 3x^2+5x-12=(x+3)(3x-4)+13 ?

The answer to 3x^2+5x-12=(x+3)(3x-4)+13 is No Solution

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3x^2+5x-12=(x+3)(3x-4)+13

3 x^{2} + 5 x - 12 = (x + 3) (3 x - 4) + 13

No Solution

Solution steps

3 x^{2} + 5 x - 12 = (x + 3) (3 x - 4) + 13

Expand

(x + 3) (3 x - 4) + 13 : 3 x^{2} + 5 x + 1

3 x^{2} + 5 x - 12 = 3 x^{2} + 5 x + 1

Move

12

to the right side

3 x^{2} + 5 x = 3 x^{2} + 5 x + 13

Subtract

3 x^{2} + 5 x

from both sides

3 x^{2} + 5 x - (3 x^{2} + 5 x) = 3 x^{2} + 5 x + 13 - (3 x^{2} + 5 x)

Simplify

0 = 13

The sides are not equal

No Solution

x^{3} + 3 x^{2} + 2 x

3 < \frac{8 - 3 x}{5} \leq 8

8 x^{2} + 3 x = 5

\frac{100 y ^{3}}{98 x y}

7 (x + 4) = 3 x + 12 + x - 5

What is the answer to 3x^2+5x-12=(x+3)(3x-4)+13 ?
The answer to 3x^2+5x-12=(x+3)(3x-4)+13 is No Solution
Solve for x: 3x^2+5x-12=(x+3)(3x-4)+13
The solution is No Solution