What is expand (g(x)=4,x+1-j=9x-5)(x) ?

The solution to expand (g(x)=4,x+1-j=9x-5)(x) is xg(x)=4x

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expand (g(x)=4,x+1-j=9x-5)(x)

expand

(g (x) = 4, x + 1 - j = 9 x - 5) (x)

xg (x) = 4 x

Solution steps

(g (x) = 4, x + 1 - j = 9 x - 5) (x)

= (x) (4 =, xg (x) + 1 - 9 = j x - 5)

Distribute parentheses

(x) g (x) = 4, x + (x) \cdot 1 + (x) (- j = 9 x) + (x) (- 5)

Apply minus-plus rules

+ (- a) = - a

(x) g (x) = 4, x + 1 \cdot (x) - j (x) = 9 x - 5 (x)

Simplify

(x) g (x) = 4, x + 1 \cdot (x) - j (x) = 9 x - 5 (x) : xg (x) = 4 x

xg (x) = 4 x

\frac{81 ( 4 n ^{2} + 2 n + 1 )}{4 n ^{2}}

e^{(1 + i) x}

u (6, - 4, - 2) v (5, 3, 4)

(vx - 2 x) (v d x + x d v)

e^{\frac{1}{2} (1 - x^{2})}

What is expand (g(x)=4,x+1-j=9x-5)(x) ?
The solution to expand (g(x)=4,x+1-j=9x-5)(x) is xg(x)=4x