What is expand (2-t)(-e^{1-t}+1) ?

The solution to expand (2-t)(-e^{1-t}+1) is -2e^{1-t}+2+e^{1-t}t-t

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expand (2-t)(-e^{1-t}+1)

expand

(2 - t) (- e^{1 - t} + 1)

- 2 e^{1 - t} + 2 + e^{1 - t} t - t

Solution steps

(2 - t) (- e^{1 - t} + 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2, b = - t, c = - e^{1 - t}, d = 1

= 2 (- e^{1 - t}) + 2 \cdot 1 + (- t) (- e^{1 - t}) + (- t) \cdot 1

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - 2 e^{1 - t} + 2 \cdot 1 + e^{1 - t} t - 1 \cdot t

Simplify

- 2 e^{1 - t} + 2 \cdot 1 + e^{1 - t} t - 1 \cdot t : - 2 e^{1 - t} + 2 + e^{1 - t} t - t

= - 2 e^{1 - t} + 2 + e^{1 - t} t - t

(a - 1)^{2} + b^{2}

(- 5)^{3} x (- 5)^{4}

(- x + 2 y = 4,) (2 x - 4 y = 3)

4.8 (x - \frac{1}{75 = - 9.6})

e^{r t} (r^{3} - 3 r^{2} + 2 r)

What is expand (2-t)(-e^{1-t}+1) ?
The solution to expand (2-t)(-e^{1-t}+1) is -2e^{1-t}+2+e^{1-t}t-t