What is expand-2(e^tsin(t)-e^tcos(t)) ?

The solution to expand-2(e^tsin(t)-e^tcos(t)) is -2e^tsin(t)+2e^tcos(t)

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expand-2(e^tsin(t)-e^tcos(t))

expand

- 2 (e^{t} sin (t) - e^{t} cos (t))

- 2 e^{t} sin (t) + 2 e^{t} cos (t)

Solution steps

- 2 (e^{t} sin (t) - e^{t} cos (t))

Apply the distributive law:

a (b - c) = ab - a c

a = - 2, b = e^{t} sin (t), c = e^{t} cos (t)

= - 2 e^{t} sin (t) - (- 2) e^{t} cos (t)

Apply minus-plus rules

- (- a) = a

= - 2 e^{t} sin (t) + 2 e^{t} cos (t)

- \frac{21 ( x + h ) ^{3}}{2}

cos (θ - (2 k + 1) π)

\frac{2 ( 19 - 8 )}{3}

(6 - 2 y - 3 z)^{2} (yz)

- \frac{1}{3} + (- 1)

What is expand-2(e^tsin(t)-e^tcos(t)) ?
The solution to expand-2(e^tsin(t)-e^tcos(t)) is -2e^tsin(t)+2e^tcos(t)