What is expand ddx(9x^2-9x-3) ?

The solution to expand ddx(9x^2-9x-3) is 9ddx^3-9ddx^2-3ddx

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expand ddx(9x^2-9x-3)

expand

dd x (9 x^{2} - 9 x - 3)

9 dd x^{3} - 9 dd x^{2} - 3 dd x

Solution steps

dd x (9 x^{2} - 9 x - 3)

Distribute parentheses

= dd x \cdot 9 x^{2} + dd x (- 9 x) + dd x (- 3)

Apply minus-plus rules

+ (- a) = - a

= 9 dd x^{2} x - 9 dd xx - 3 dd x

Simplify

9 dd x^{2} x - 9 dd xx - 3 dd x : 9 dd x^{3} - 9 dd x^{2} - 3 dd x

= 9 dd x^{3} - 9 dd x^{2} - 3 dd x

5 (r + 9) - 2 (1 - r = 1)

\frac{2 x + 24}{( x + 3 ) ( x + 4 ) ( x + 5 )}

\frac{k}{( s + 4 ) ( s + 6 ) ( s + 10 )}

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\frac{2 ( x - 1 )}{x ^{2} ( 6 x + 17 )}

What is expand ddx(9x^2-9x-3) ?
The solution to expand ddx(9x^2-9x-3) is 9ddx^3-9ddx^2-3ddx