What is expand 4/((x-1)^2(x-3)(x+1)) ?

The solution to expand 4/((x-1)^2(x-3)(x+1)) is 4/(x^4-4x^3+2x^2+4x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 4/((x-1)^2(x-3)(x+1))

expand

\frac{4}{( x - 1 ) ^{2} ( x - 3 ) ( x + 1 )}

\frac{4}{x ^{4} - 4 x ^{3} + 2 x ^{2} + 4 x - 3}

Solution steps

\frac{4}{( x - 1 ) ^{2} ( x - 3 ) ( x + 1 )}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{4}{( x ^{2} - 2 x + 1 ) ( x - 3 ) ( x + 1 )}

Expand

(x^{2} - 2 x + 1) (x - 3) (x + 1) : x^{4} - 4 x^{3} + 2 x^{2} + 4 x - 3

= \frac{4}{x ^{4} - 4 x ^{3} + 2 x ^{2} + 4 x - 3}

\frac{( x - 1 ) z}{2 z - 4 t + 1}

- \frac{1}{2 ( 5 + 4 s - s ^{2} )}

\frac{( x ^{2} + 7 ) ^{2}}{x ^{5}}

(- 4 x B)^{4}

(- 2 + 3 d = 6,) (2 n - 2 d = 4)

What is expand 4/((x-1)^2(x-3)(x+1)) ?
The solution to expand 4/((x-1)^2(x-3)(x+1)) is 4/(x^4-4x^3+2x^2+4x-3)