What is expand ((x-5)(x+1)(x-1))/(3x+2) ?

The solution to expand ((x-5)(x+1)(x-1))/(3x+2) is (x^3-x-5x^2+5)/(3x+2)

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expand ((x-5)(x+1)(x-1))/(3x+2)

expand

\frac{( x - 5 ) ( x + 1 ) ( x - 1 )}{3 x + 2}

\frac{x ^{3} - x - 5 x ^{2} + 5}{3 x + 2}

Solution steps

\frac{( x - 5 ) ( x + 1 ) ( x - 1 )}{3 x + 2}

Expand

(x - 5) (x + 1) (x - 1) : x^{3} - x - 5 x^{2} + 5

= \frac{x ^{3} - x - 5 x ^{2} + 5}{3 x + 2}

(- \frac{1}{x ^{2}})^{8}

P (8, - 7) Q (13, 7)

\frac{3}{4 ( 28 x + 16 y - 20 )}

- 4 x [c (x - c)^{2}]

\frac{3 ( - 2 x - 3 y + 6 ) ^{2}}{2}

What is expand ((x-5)(x+1)(x-1))/(3x+2) ?
The solution to expand ((x-5)(x+1)(x-1))/(3x+2) is (x^3-x-5x^2+5)/(3x+2)