What is expand A(2,1)B(3,-4)YC(-1,3) ?

The solution to expand A(2,1)B(3,-4)YC(-1,3) is 3(2*1,)(-1*3,)ABYC,-4(2*1,)(-1*3,)ABYC

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expand A(2,1)B(3,-4)YC(-1,3)

expand

A (2, 1) B (3, - 4) Y C (- 1, 3)

3 (2 \cdot 1,) (- 1 \cdot 3,) A B Y C, - 4 (2 \cdot 1,) (- 1 \cdot 3,) A B Y C

Solution steps

A (2, 1) B (3, - 4) Y C (- 1, 3)

= (2 \cdot 1,) (3, - 4) (- 1 \cdot 3,) A B Y C

Apply the distributive law:

a (b - c) = ab - a c

a = A (2, 1) B Y C (- 1, 3), b = 3,, c = 4

= A (2, 1) B Y C (- 1, 3) \cdot 3, - A (2, 1) B Y C (- 1, 3) \cdot 4

= 3 (2 \cdot 1,) (- 1 \cdot 3,) A B Y C, - 4 (2 \cdot 1,) (- 1 \cdot 3,) A B Y C

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\frac{2}{x ( x + 1 ) ^{2}}

\frac{1 ^{2}}{S ( S ^{2} + 1 ^{2} )}

A (6, 0) B (0, - 6)

(c x + z)^{2} + x^{2} s^{2}

What is expand A(2,1)B(3,-4)YC(-1,3) ?
The solution to expand A(2,1)B(3,-4)YC(-1,3) is 3(2*1,)(-1*3,)ABYC,-4(2*1,)(-1*3,)ABYC