What is expand (e^{6x}-1)(e^{3x}+4) ?

The solution to expand (e^{6x}-1)(e^{3x}+4) is e^{9x}+4e^{6x}-e^{3x}-4

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expand (e^{6x}-1)(e^{3x}+4)

expand

(e^{6 x} - 1) (e^{3 x} + 4)

e^{9 x} + 4 e^{6 x} - e^{3 x} - 4

Solution steps

(e^{6 x} - 1) (e^{3 x} + 4)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = e^{6 x}, b = - 1, c = e^{3 x}, d = 4

= e^{6 x} e^{3 x} + e^{6 x} \cdot 4 + (- 1) e^{3 x} + (- 1) \cdot 4

Apply minus-plus rules

+ (- a) = - a

= e^{6 x} e^{3 x} + 4 e^{6 x} - 1 \cdot e^{3 x} - 1 \cdot 4

Simplify

e^{6 x} e^{3 x} + 4 e^{6 x} - 1 \cdot e^{3 x} - 1 \cdot 4 : e^{9 x} + 4 e^{6 x} - e^{3 x} - 4

= e^{9 x} + 4 e^{6 x} - e^{3 x} - 4

- ((6, - 3) - (- 3, 4))

l (0, 1) m (1 - 2) n (- 21) (x + 2, y + 3)

2 x^{2} + 5 x - 3 - x^{2} - 9 x + 4

3^{(h + 2) h + 1}

(y^{2} + 1) d x + (x^{2} + 1) d y

What is expand (e^{6x}-1)(e^{3x}+4) ?
The solution to expand (e^{6x}-1)(e^{3x}+4) is e^{9x}+4e^{6x}-e^{3x}-4