What is expand ((3yz-5x)^2)/(225) ?

The solution to expand ((3yz-5x)^2)/(225) is (y^2z^2}{25}-(2yzx)/(15)+\frac{x^2)/9

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expand ((3yz-5x)^2)/(225)

expand

\frac{( 3 yz - 5 x ) ^{2}}{225}

\frac{y ^{2} z ^{2}}{25} - \frac{2 yz x}{15} + \frac{x ^{2}}{9}

Solution steps

\frac{( 3 yz - 5 x ) ^{2}}{225}

(3 yz - 5 x)^{2} = 9 y^{2} z^{2} - 30 yz x + 25 x^{2}

= \frac{9 y ^{2} z ^{2} - 30 yz x + 25 x ^{2}}{225}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 y ^{2} z ^{2} - 30 yz x + 25 x ^{2}}{225} = \frac{9 y ^{2} z ^{2}}{225} - \frac{30 yz x}{225} + \frac{25 x ^{2}}{225}

= \frac{9 y ^{2} z ^{2}}{225} - \frac{30 yz x}{225} + \frac{25 x ^{2}}{225}

Cancel

\frac{9 y ^{2} z ^{2}}{225} : \frac{y ^{2} z ^{2}}{25}

= \frac{y ^{2} z ^{2}}{25} - \frac{30 yz x}{225} + \frac{25 x ^{2}}{225}

Cancel

\frac{30 yz x}{225} : \frac{2 yz x}{15}

= \frac{y ^{2} z ^{2}}{25} - \frac{2 yz x}{15} + \frac{25 x ^{2}}{225}

Cancel

\frac{25 x ^{2}}{225} : \frac{x ^{2}}{9}

= \frac{y ^{2} z ^{2}}{25} - \frac{2 yz x}{15} + \frac{x ^{2}}{9}

\frac{( x + 4 ) ^{2}}{x - 7}

\frac{x}{( x ^{2} + 1 ) ( x ^{2} + x + 3 )}

e^{x} (e^{x} x - e^{x})

2 π (6 x + 3) 37

0.981 t - 0.0981 (1 - e^{- 10 t})

What is expand ((3yz-5x)^2)/(225) ?
The solution to expand ((3yz-5x)^2)/(225) is (y^2z^2}{25}-(2yzx)/(15)+\frac{x^2)/9