What is expand ((x-1)(x+1))/((x-2)(x-3)) ?

The solution to expand ((x-1)(x+1))/((x-2)(x-3)) is (x^2-1)/(x^2-5x+6)

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expand ((x-1)(x+1))/((x-2)(x-3))

expand

\frac{( x - 1 ) ( x + 1 )}{( x - 2 ) ( x - 3 )}

\frac{x ^{2} - 1}{x ^{2} - 5 x + 6}

Solution steps

\frac{( x - 1 ) ( x + 1 )}{( x - 2 ) ( x - 3 )}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{( x - 1 ) ( x + 1 )}{x ^{2} - 5 x + 6}

Expand

(x - 1) (x + 1) : x^{2} - 1

= \frac{x ^{2} - 1}{x ^{2} - 5 x + 6}

4 x y^{2} d x + (x^{2} + 1) d y

d e l (x^{2} + y^{2} + z^{2})

- 0.01 (- 6) (0)^{2}

3 (3 x - 2 = 4)

(0.3 e^{- t} + 0.4 + 0.3 e^{t})^{2}

What is expand ((x-1)(x+1))/((x-2)(x-3)) ?
The solution to expand ((x-1)(x+1))/((x-2)(x-3)) is (x^2-1)/(x^2-5x+6)