What are the solutions to the equation 2x^2+2x-12=-12 ?

The solutions to the equation 2x^2+2x-12=-12 are x=0,x=-1

Find the zeros of 2x^2+2x-12=-12

The zeros of 2x^2+2x-12=-12 are x=0,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 2 x - 12 = - 12

x = 0, x = - 1

Solution steps

2 x^{2} + 2 x - 12 = - 12

Move

12

to the left side

2 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

2^{2} - 4 \cdot 2 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 2}, x_{2} = \frac{- 2 - 2}{2 \cdot 2}

x = \frac{- 2 + 2}{2 \cdot 2} : 0

x = \frac{- 2 - 2}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

\frac{v}{5} - 15 > 4

3 x - x + 7 x + 12 = 3 x + 9

x^{2} - 2 x + 3 = 2 x^{2} - 4 x + 3

14 (t + 9) = 84

x^{2} - 1 < 2

What are the solutions to the equation 2x^2+2x-12=-12 ?
The solutions to the equation 2x^2+2x-12=-12 are x=0,x=-1
Find the zeros of 2x^2+2x-12=-12
The zeros of 2x^2+2x-12=-12 are x=0,x=-1