What is expand (2x-3)(4x^2-6x=9) ?

The solution to expand (2x-3)(4x^2-6x=9) is 8x^3-12x^2=9

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expand (2x-3)(4x^2-6x=9)

expand

(2 x - 3) (4 x^{2} - 6 x = 9)

8 x^{3} - 12 x^{2} = 9

Solution steps

(2 x - 3) (4 x^{2} - 6 x = 9)

= (2 x - 3) (4 x^{2} - 6 \cdot 9 = x)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = - 3, c = 4 x^{2}, d = - 6 x = 9

= 2 x \cdot 4 x^{2} + 2 x (- 6 x = 9) + (- 3) \cdot 4 x^{2} + (- 3) (- 6 x = 9)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

2 \cdot 4 x^{2} x - 2 \cdot 6 xx = 9 - 3 \cdot 4 x^{2} + 3 \cdot 6 x = 9

Expand

2 \cdot 4 x^{2} x - 2 \cdot 6 xx : 8 x^{3} - 12 x^{2}

8 x^{3} - 12 x^{2} = 9

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What is expand (2x-3)(4x^2-6x=9) ?
The solution to expand (2x-3)(4x^2-6x=9) is 8x^3-12x^2=9