What is expand ((2x-7)(2x+7))/4 ?

The solution to expand ((2x-7)(2x+7))/4 is x^2-49/4

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expand ((2x-7)(2x+7))/4

expand

\frac{( 2 x - 7 ) ( 2 x + 7 )}{4}

x^{2} - \frac{49}{4}

Solution steps

\frac{( 2 x - 7 ) ( 2 x + 7 )}{4}

Expand

(2 x - 7) (2 x + 7) : 4 x^{2} - 49

= \frac{4 x ^{2} - 49}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 49}{4} = \frac{4 x ^{2}}{4} - \frac{49}{4}

= \frac{4 x ^{2}}{4} - \frac{49}{4}

Divide the numbers:

\frac{4}{4} = 1

= x^{2} - \frac{49}{4}

(4 x) (5 x)

\frac{10 ( - j sin ( n wt ) - 1 )}{j w n}

\frac{1}{( s + 1 ) ( s ^{2} + 3 + 4 s )}

\frac{2 ( x ^{5} - 4 )}{x - 4}

\frac{16}{x ^{2} \cdot ( x - 4 )}

What is expand ((2x-7)(2x+7))/4 ?
The solution to expand ((2x-7)(2x+7))/4 is x^2-49/4