What is expand (x+2y-5=0)(4x+2y+3) ?

The solution to expand (x+2y-5=0)(4x+2y+3) is 4x^2+10xy+3x+4y^2+6y-5=0

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expand (x+2y-5=0)(4x+2y+3)

expand

(x + 2 y - 5 = 0) (4 x + 2 y + 3)

4 x^{2} + 10 x y + 3 x + 4 y^{2} + 6 y - 5 = 0

Solution steps

(x + 2 y - 5 = 0) (4 x + 2 y + 3)

= (x + 2 y - 5 \cdot 0 =) (4 x + 2 y + 3)

Distribute parentheses

= x \cdot 4 x + x \cdot 2 y + x \cdot 3 + 2 y \cdot 4 x + 2 y \cdot 2 y + 2 y \cdot 3 + (- 5 = 0) \cdot 4 x + (- 5 = 0) \cdot 2 y + (- 5 = 0) \cdot 3

Apply minus-plus rules

+ (- a) = - a

4 xx + 2 x y + 3 x + 2 \cdot 4 x y + 2 \cdot 2 yy + 2 \cdot 3 y - 5 = 0 \cdot 4 x - 5 = 0 \cdot 2 y - 5 = 0 \cdot 3

Simplify

4 xx + 2 x y + 3 x + 2 \cdot 4 x y + 2 \cdot 2 yy + 2 \cdot 3 y - 5 = 0 \cdot 4 x - 5 = 0 \cdot 2 y - 5 = 0 \cdot 3 : 4 x^{2} + 10 x y + 3 x + 4 y^{2} + 6 y - 5 = 0

4 x^{2} + 10 x y + 3 x + 4 y^{2} + 6 y - 5 = 0

\frac{3}{x ^{- 2}}

- 2 (5 m + 4 = 12)

\frac{4 x + 7}{( x + 2 ) ( x + 3 )}

f (3 x^{2} + 2 x + 1) d x

(144 - 16 y^{2}) d y

What is expand (x+2y-5=0)(4x+2y+3) ?
The solution to expand (x+2y-5=0)(4x+2y+3) is 4x^2+10xy+3x+4y^2+6y-5=0