What is expand h(x)inversa(9-2x) ?

The solution to expand h(x)inversa(9-2x) is 9erainhxvs-2erainhx^2vs

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expand h(x)inversa(9-2x)

expand

h (x) in v ers a (9 - 2 x)

9 er ainh xv s - 2 er ainh x^{2} v s

Solution steps

h (x) in v ers a (9 - 2 x)

= er ainh (x) v s (9 - 2 x)

Apply the distributive law:

a (b - c) = ab - a c

a = h (x) in v ers a, b = 9, c = 2 x

= h (x) in v ers a \cdot 9 - h (x) in v ers a \cdot 2 x

= 9 er ainh (x) v s - 2 er ainh (x) xv s

Simplify

9 er ainh (x) v s - 2 er ainh (x) xv s : 9 er ainh xv s - 2 er ainh x^{2} v s

= 9 er ainh xv s - 2 er ainh x^{2} v s

\frac{( 2 x ( 200 - 4 x ) )}{3}

7 e (5 e - 7) + 2 (9 e^{2} - 8)

(X) + (Y Z)

(7 e - 4 f)^{2}

\frac{30}{\frac{1}{3}}

What is expand h(x)inversa(9-2x) ?
The solution to expand h(x)inversa(9-2x) is 9erainhxvs-2erainhx^2vs