What is expand ((y-1)(2xz+1))/y ?

The solution to expand ((y-1)(2xz+1))/y is 2xz+1-(2xz)/y-1/y

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expand ((y-1)(2xz+1))/y

expand

\frac{( y - 1 ) ( 2 x z + 1 )}{y}

2 x z + 1 - \frac{2 x z}{y} - \frac{1}{y}

Solution steps

\frac{( y - 1 ) ( 2 x z + 1 )}{y}

Expand

(y - 1) (2 x z + 1) : 2 y x z + y - 2 x z - 1

= \frac{2 y x z + y - 2 x z - 1}{y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 y x z + y - 2 x z - 1}{y} = \frac{2 y x z}{y} + \frac{y}{y} - \frac{2 x z}{y} - \frac{1}{y}

= \frac{2 y x z}{y} + \frac{y}{y} - \frac{2 x z}{y} - \frac{1}{y}

Apply rule

\frac{a}{a} = 1

\frac{y}{y} = 1

= \frac{2 y x z}{y} + 1 - \frac{2 x z}{y} - \frac{1}{y}

Cancel

\frac{2 y x z}{y} : 2 x z

= 2 x z + 1 - \frac{2 x z}{y} - \frac{1}{y}

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What is expand ((y-1)(2xz+1))/y ?
The solution to expand ((y-1)(2xz+1))/y is 2xz+1-(2xz)/y-1/y