What is expand (2(x-2)(x+1))/((x+3)^2) ?

The solution to expand (2(x-2)(x+1))/((x+3)^2) is (2x^2-2x-4)/(x^2+6x+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(x-2)(x+1))/((x+3)^2)

expand

\frac{2 ( x - 2 ) ( x + 1 )}{( x + 3 ) ^{2}}

\frac{2 x ^{2} - 2 x - 4}{x ^{2} + 6 x + 9}

Solution steps

\frac{2 ( x - 2 ) ( x + 1 )}{( x + 3 ) ^{2}}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{2 ( x - 2 ) ( x + 1 )}{x ^{2} + 6 x + 9}

Expand

2 (x - 2) (x + 1) : 2 x^{2} - 2 x - 4

= \frac{2 x ^{2} - 2 x - 4}{x ^{2} + 6 x + 9}

1 6^{4}

\frac{1}{( t ^{3} + 4 ) ^{5}}

\frac{( x - 2 ) ( x + 1 )}{x ^{2}}

1 6^{2}

20 (1 + x) e^{(4) (x^{3}) (1 + x)}

What is expand (2(x-2)(x+1))/((x+3)^2) ?
The solution to expand (2(x-2)(x+1))/((x+3)^2) is (2x^2-2x-4)/(x^2+6x+9)