What is expand (f(x^2)-f(2x+4))/h ?

The solution to expand (f(x^2)-f(2x+4))/h is (fx^2)/h-(2fx)/h-(4f)/h

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expand (f(x^2)-f(2x+4))/h

expand

\frac{f ( x ^{2} ) - f ( 2 x + 4 )}{h}

\frac{f x ^{2}}{h} - \frac{2 f x}{h} - \frac{4 f}{h}

Solution steps

\frac{f ( x ^{2} ) - f ( 2 x + 4 )}{h}

Remove parentheses:

(a) = a

= \frac{f x ^{2} - f ( 2 x + 4 )}{h}

Expand

f x^{2} - f (2 x + 4) : f x^{2} - 2 f x - 4 f

= \frac{f x ^{2} - 2 f x - 4 f}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{f x ^{2} - 2 f x - 4 f}{h} = \frac{f x ^{2}}{h} - \frac{2 f x}{h} - \frac{4 f}{h}

= \frac{f x ^{2}}{h} - \frac{2 f x}{h} - \frac{4 f}{h}

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What is expand (f(x^2)-f(2x+4))/h ?
The solution to expand (f(x^2)-f(2x+4))/h is (fx^2)/h-(2fx)/h-(4f)/h