What is expand (k(k+1)(k+2))/6 ?

The solution to expand (k(k+1)(k+2))/6 is (k^3)/6+(k^2)/2+k/3

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expand (k(k+1)(k+2))/6

expand

\frac{k ( k + 1 ) ( k + 2 )}{6}

\frac{k ^{3}}{6} + \frac{k ^{2}}{2} + \frac{k}{3}

Solution steps

\frac{k ( k + 1 ) ( k + 2 )}{6}

Expand

k (k + 1) (k + 2) : k^{3} + 3 k^{2} + 2 k

= \frac{k ^{3} + 3 k ^{2} + 2 k}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{k ^{3} + 3 k ^{2} + 2 k}{6} = \frac{k ^{3}}{6} + \frac{3 k ^{2}}{6} + \frac{2 k}{6}

= \frac{k ^{3}}{6} + \frac{3 k ^{2}}{6} + \frac{2 k}{6}

Cancel

\frac{3 k ^{2}}{6} : \frac{k ^{2}}{2}

= \frac{k ^{3}}{6} + \frac{k ^{2}}{2} + \frac{2 k}{6}

Cancel

\frac{2 k}{6} : \frac{k}{3}

= \frac{k ^{3}}{6} + \frac{k ^{2}}{2} + \frac{k}{3}

(y - 2 x) d x

j (z - e^{T (j - 1)}) (z - e^{T (- j - 1)})

\frac{( x - 5 )}{x ( x - 7 )}

- 3 (2 x + 5 y = 15)

\frac{( x + 2 ) ^{2}}{( x + 2 j ) ( x - 2 j )}

What is expand (k(k+1)(k+2))/6 ?
The solution to expand (k(k+1)(k+2))/6 is (k^3)/6+(k^2)/2+k/3