What is expand ((3-2x)^3)/3 ?

The solution to expand ((3-2x)^3)/3 is -(8x^3)/3+12x^2-18x+9

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expand ((3-2x)^3)/3

expand

\frac{( 3 - 2 x ) ^{3}}{3}

- \frac{8 x ^{3}}{3} + 12 x^{2} - 18 x + 9

Solution steps

\frac{( 3 - 2 x ) ^{3}}{3}

(3 - 2 x)^{3} = 27 - 54 x + 36 x^{2} - 8 x^{3}

= \frac{27 - 54 x + 36 x ^{2} - 8 x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 - 54 x + 36 x ^{2} - 8 x ^{3}}{3} = \frac{27}{3} - \frac{54 x}{3} + \frac{36 x ^{2}}{3} - \frac{8 x ^{3}}{3}

= \frac{27}{3} - \frac{54 x}{3} + \frac{36 x ^{2}}{3} - \frac{8 x ^{3}}{3}

Divide the numbers:

\frac{27}{3} = 9

= 9 - \frac{54 x}{3} + \frac{36 x ^{2}}{3} - \frac{8 x ^{3}}{3}

Divide the numbers:

\frac{54}{3} = 18

= 9 - 18 x + \frac{36 x ^{2}}{3} - \frac{8 x ^{3}}{3}

Divide the numbers:

\frac{36}{3} = 12

= 9 - 18 x + 12 x^{2} - \frac{8 x ^{3}}{3}

Rewrite in standard form

= - \frac{8 x ^{3}}{3} + 12 x^{2} - 18 x + 9

\frac{2 x}{( ( x - 2 ) ( x + 2 ) )}

\frac{3 ( x + 1 )}{2 x}

\frac{24}{( s ^{2} + 4 ) ( s - 12 )}

10 (0.8 - 0.3 = 0.27)

(x - 2)^{2} d x

What is expand ((3-2x)^3)/3 ?
The solution to expand ((3-2x)^3)/3 is -(8x^3)/3+12x^2-18x+9