What is expand ((3b-3)3)/(2b^9) ?

The solution to expand ((3b-3)3)/(2b^9) is 9/(2b^8)-9/(2b^9)

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expand ((3b-3)3)/(2b^9)

expand

\frac{( 3 b - 3 ) 3}{2 b ^{9}}

\frac{9}{2 b ^{8}} - \frac{9}{2 b ^{9}}

Solution steps

\frac{( 3 b - 3 ) \cdot 3}{2 b ^{9}}

Expand

(3 b - 3) \cdot 3 : 9 b - 9

= \frac{9 b - 9}{2 b ^{9}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 b - 9}{2 b ^{9}} = \frac{9 b}{2 b ^{9}} - \frac{9}{2 b ^{9}}

= \frac{9 b}{2 b ^{9}} - \frac{9}{2 b ^{9}}

Cancel

\frac{9 b}{2 b ^{9}} : \frac{9}{2 b ^{8}}

= \frac{9}{2 b ^{8}} - \frac{9}{2 b ^{9}}

3 (y + 100 = 3000)

\frac{94}{3 ( 1 - 6 x ) ^{2}}

tan (π (x - 0.5))

2 x (y - 3) - 3 δ (y - 1)

2 + \frac{1}{2}

What is expand ((3b-3)3)/(2b^9) ?
The solution to expand ((3b-3)3)/(2b^9) is 9/(2b^8)-9/(2b^9)