What is factor (2k^3+9k^2+13k+6)/6 ?

The solution to factor (2k^3+9k^2+13k+6)/6 is ((k+1)(2k+3)(k+2))/6

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factor (2k^3+9k^2+13k+6)/6

factor

\frac{2 k ^{3} + 9 k ^{2} + 13 k + 6}{6}

\frac{( k + 1 ) ( 2 k + 3 ) ( k + 2 )}{6}

Solution steps

\frac{2 k ^{3} + 9 k ^{2} + 13 k + 6}{6}

Factor

2 k^{3} + 9 k^{2} + 13 k + 6 : (k + 1) (2 k + 3) (k + 2)

= \frac{( k + 1 ) ( 2 k + 3 ) ( k + 2 )}{6}

x^{2} - 13 x + 40 < 0

x^{2} + 2 x y - 63 y^{2}

2 k^{2} + 7 k + 5

10 p^{3} - 1960 p

4 (3 - x) + 6 x = 3 x + 12 + 2 x

What is factor (2k^3+9k^2+13k+6)/6 ?
The solution to factor (2k^3+9k^2+13k+6)/6 is ((k+1)(2k+3)(k+2))/6