What is expand 3(4-12x)-6(2x-3=36+2(3x+2)) ?

The solution to expand 3(4-12x)-6(2x-3=36+2(3x+2)) is -48x+30=-36x+12

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expand 3(4-12x)-6(2x-3=36+2(3x+2))

expand

3 (4 - 12 x) - 6 (2 x - 3 = 36 + 2 (3 x + 2))

- 48 x + 30 = - 36 x + 12

Solution steps

3 (4 - 12 x) - 6 (2 x - 3 = 36 + 2 (3 x + 2))

= 3 (4 - 12 x) - 6 (2 x - 3 \cdot 36 = + 2 (3 x + 2))

Expand

3 (4 - 12 x) : 12 - 36 x

= 12 - 36 x - 6 (2 x - 3 = 36 + 2 (3 x + 2))

Expand

- 6 (2 x - 3 = 36 + 2 (3 x + 2)) : - 12 x + 18 = - 36 x + 12

12 - 36 x - 12 x + 18 = - 36 x + 12

Expand

12 - 36 x - 12 x + 18 : - 48 x + 30

- 48 x + 30 = - 36 x + 12

\frac{4 ( x + h ) + 7}{7 ( x + h ) - 6}

z - (\frac{3}{5 + 3 i})

A (0, - 6) B (5, - 6)

\frac{1}{( s + 4 ) ( s + 8 )}

\frac{( 2 a - 3 b ) ^{2}}{36}

What is expand 3(4-12x)-6(2x-3=36+2(3x+2)) ?
The solution to expand 3(4-12x)-6(2x-3=36+2(3x+2)) is -48x+30=-36x+12