What is expand 4(sec^2(x^2+3x+2)(2x+3)) ?

The solution to expand 4(sec^2(x^2+3x+2)(2x+3)) is 8xsec^2(x^2+3x+2)+12sec^2(x^2+3x+2)

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expand 4(sec^2(x^2+3x+2)(2x+3))

expand

4 (sec^{2} (x^{2} + 3 x + 2) (2 x + 3))

8 x sec^{2} (x^{2} + 3 x + 2) + 12 sec^{2} (x^{2} + 3 x + 2)

Solution steps

4 (sec^{2} (x^{2} + 3 x + 2) (2 x + 3))

Remove parentheses:

(a) = a

= 4 sec^{2} (x^{2} + 3 x + 2) (2 x + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = 4 sec^{2} (x^{2} + 3 x + 2), b = 2 x, c = 3

= 4 sec^{2} (x^{2} + 3 x + 2) \cdot 2 x + 4 sec^{2} (x^{2} + 3 x + 2) \cdot 3

= 4 \cdot 2 x sec^{2} (x^{2} + 3 x + 2) + 4 \cdot 3 sec^{2} (x^{2} + 3 x + 2)

Simplify

4 \cdot 2 x sec^{2} (x^{2} + 3 x + 2) + 4 \cdot 3 sec^{2} (x^{2} + 3 x + 2) : 8 x sec^{2} (x^{2} + 3 x + 2) + 12 sec^{2} (x^{2} + 3 x + 2)

= 8 x sec^{2} (x^{2} + 3 x + 2) + 12 sec^{2} (x^{2} + 3 x + 2)

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(- 3 x^{3} - 8 x^{6}) (10 e^{x} + 2)

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What is expand 4(sec^2(x^2+3x+2)(2x+3)) ?
The solution to expand 4(sec^2(x^2+3x+2)(2x+3)) is 8xsec^2(x^2+3x+2)+12sec^2(x^2+3x+2)