What is expand (e^{-x}-1)(e^{-x}+1) ?

The solution to expand (e^{-x}-1)(e^{-x}+1) is e^{-2x}-1

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expand (e^{-x}-1)(e^{-x}+1)

expand

(e^{- x} - 1) (e^{- x} + 1)

e^{- 2 x} - 1

Solution steps

(e^{- x} - 1) (e^{- x} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{- x}, b = 1

= (e^{- x})^{2} - 1^{2}

Simplify

(e^{- x})^{2} - 1^{2} : e^{- 2 x} - 1

= e^{- 2 x} - 1

e v a l u a t e (10 - 4 i) + (5 + i)

i (- 4, 5) j (- 4, - 3) k (5, - 8) l (5, 0)

e^{(x - 2)^{8}}

2 (- 2 ln (3) + 3)

4 e^{2 x} (e^{2 x} - 1)^{2}

What is expand (e^{-x}-1)(e^{-x}+1) ?
The solution to expand (e^{-x}-1)(e^{-x}+1) is e^{-2x}-1