What is expand-2e^x(sin(x)+cos(x)) ?

The solution to expand-2e^x(sin(x)+cos(x)) is -2e^xsin(x)-2e^xcos(x)

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expand-2e^x(sin(x)+cos(x))

expand

- 2 e^{x} (sin (x) + cos (x))

- 2 e^{x} sin (x) - 2 e^{x} cos (x)

Solution steps

- 2 e^{x} (sin (x) + cos (x))

Apply the distributive law:

a (b + c) = ab + a c

a = - 2 e^{x}, b = sin (x), c = cos (x)

= - 2 e^{x} sin (x) + (- 2 e^{x}) cos (x)

Apply minus-plus rules

+ (- a) = - a

= - 2 e^{x} sin (x) - 2 e^{x} cos (x)

\frac{2}{3} (z + 5 = y)

\frac{d}{d t} ((x) (x^{2} + t^{2}))

\frac{1}{s ( 5 s + 4 )}

lo g_{10} (27) (81)

(1 + δ) (1 + δ)

What is expand-2e^x(sin(x)+cos(x)) ?
The solution to expand-2e^x(sin(x)+cos(x)) is -2e^xsin(x)-2e^xcos(x)