What is the d/(dt)((w)((w-2)(w-3))) ?

The d/(dt)((w)((w-2)(w-3))) is 3t^2-10t+6

What is the first d/(dt)((w)((w-2)(w-3))) ?

The first d/(dt)((w)((w-2)(w-3))) is 3t^2-10t+6

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\frac{d}{d t} ((t) ((t - 2) (t - 3)))

3 t^{2} - 10 t + 6

Solution steps

\frac{d}{d t} ((t) ((t - 2) (t - 3)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = (t - 2) (t - 3)

= \frac{d t}{d t} (t - 2) (t - 3) + \frac{d}{d t} ((t - 2) (t - 3)) t

\frac{d t}{d t} = 1

\frac{d}{d t} ((t - 2) (t - 3)) = 2 t - 5

= 1 \cdot (t - 2) (t - 3) + (2 t - 5) t

Simplify

1 \cdot (t - 2) (t - 3) + (2 t - 5) t : 3 t^{2} - 10 t + 6

= 3 t^{2} - 10 t + 6

(4, - 6, 1) x (2, 0, 5)

\frac{t + h}{2 ( t + h ) + 6}

\frac{( x ^{2} )}{( x - 5 ) ^{3}}

\frac{1}{y ( 1 - y ^{2} )}

1000 (2 - e^{p})

What is the d/(dt)((w)((w-2)(w-3))) ?
The d/(dt)((w)((w-2)(w-3))) is 3t^2-10t+6
What is the first d/(dt)((w)((w-2)(w-3))) ?
The first d/(dt)((w)((w-2)(w-3))) is 3t^2-10t+6