What is the d/(dt)((x)(9+sin(x))) ?

The d/(dt)((x)(9+sin(x))) is 9+sin(t)+tcos(t)

What is the first d/(dt)((x)(9+sin(x))) ?

The first d/(dt)((x)(9+sin(x))) is 9+sin(t)+tcos(t)

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\frac{d}{d t} ((t) (9 + sin (t)))

9 + sin (t) + t cos (t)

Solution steps

\frac{d}{d t} ((t) (9 + sin (t)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 9 + sin (t)

= \frac{d t}{d t} (9 + sin (t)) + \frac{d}{d t} (9 + sin (t)) t

\frac{d t}{d t} = 1

\frac{d}{d t} (9 + sin (t)) = cos (t)

= 1 \cdot (9 + sin (t)) + cos (t) t

Simplify

= 9 + sin (t) + t cos (t)

\frac{2 ( x + h ) + 3}{x + h - 1}

\frac{d x}{( 6 x + 1 ) ^{4}}

e^{- i (x + \frac{π}{4})}

\frac{8}{3 ( x + 2 ) ^{3}}

a - 2 a + b + a + b - c + a

What is the d/(dt)((x)(9+sin(x))) ?
The d/(dt)((x)(9+sin(x))) is 9+sin(t)+tcos(t)
What is the first d/(dt)((x)(9+sin(x))) ?
The first d/(dt)((x)(9+sin(x))) is 9+sin(t)+tcos(t)