What is expand (y-4)(y^2=+4y+16) ?

The solution to expand (y-4)(y^2=+4y+16) is y^3=-16y-64

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expand (y-4)(y^2=+4y+16)

expand

(y - 4) (y^{2} = + 4 y + 16)

y^{3} = - 16 y - 64

Solution steps

(y - 4) (y^{2} = + 4 y + 16)

= (y - 4) (= y^{2} + 4 y + 16)

Distribute parentheses

y y^{2} = y \cdot 4 y + y \cdot 16 + (- 4) y^{2} = (- 4) \cdot 4 y + (- 4) \cdot 16

Apply minus-plus rules

+ (- a) = - a

y^{2} y = 4 yy + 16 y - 4 y^{2} = - 4 \cdot 4 y - 4 \cdot 16

Simplify

y^{2} y = 4 yy + 16 y - 4 y^{2} = - 4 \cdot 4 y - 4 \cdot 16 : y^{3} = - 16 y - 64

y^{3} = - 16 y - 64

e^{4 x} \cdot (e^{4 x} + 4 x e^{4 x})

e^{x} (- x^{2} + 7)

(x^{2} - x y) \frac{d y}{d x}

\frac{7 ( 373 - 7 )}{18}

x (x + y) d y - y^{2}

What is expand (y-4)(y^2=+4y+16) ?
The solution to expand (y-4)(y^2=+4y+16) is y^3=-16y-64