What is expand (3x)/((x-2)(x^3-8)) ?

The solution to expand (3x)/((x-2)(x^3-8)) is (3x)/(x^4-8x-2x^3+16)

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expand (3x)/((x-2)(x^3-8))

expand

\frac{3 x}{( x - 2 ) ( x ^{3} - 8 )}

\frac{3 x}{x ^{4} - 8 x - 2 x ^{3} + 16}

Solution steps

\frac{3 x}{( x - 2 ) ( x ^{3} - 8 )}

Expand

(x - 2) (x^{3} - 8) : x^{4} - 8 x - 2 x^{3} + 16

= \frac{3 x}{x ^{4} - 8 x - 2 x ^{3} + 16}

\frac{x + 4}{x ^{2} ( x ^{2} + 1 )}

\frac{1}{2 ( p + q )}

e P (- 9, - 4) Q (- 4, - 5)

a (1, 2, 4, 5, 0, 7, 3, - 4 - 1, 7, - 6, 2)

- 2 (ln (3) + 1)

What is expand (3x)/((x-2)(x^3-8)) ?
The solution to expand (3x)/((x-2)(x^3-8)) is (3x)/(x^4-8x-2x^3+16)