What is expand ((y-2)dy)/((y-3)(y-1)) ?

The solution to expand ((y-2)dy)/((y-3)(y-1)) is (ydy-2dy)/(y^2-4y+3)

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expand ((y-2)dy)/((y-3)(y-1))

expand

\frac{( y - 2 ) d y}{( y - 3 ) ( y - 1 )}

\frac{y d y - 2 d y}{y ^{2} - 4 y + 3}

Solution steps

\frac{( y - 2 ) d y}{( y - 3 ) ( y - 1 )}

Expand

(y - 3) (y - 1) : y^{2} - 4 y + 3

= \frac{( y - 2 ) d y}{y ^{2} - 4 y + 3}

Expand

(y - 2) d y : y d y - 2 d y

= \frac{y d y - 2 d y}{y ^{2} - 4 y + 3}

lo g_{10} (0.1)

\frac{y ( 3 - y ) ^{2}}{2}

\frac{( 2 + x ) ( 7 - x )}{( 5 - x ) ( 4 + x )}

\frac{6 ( x + h )}{( x + h ) + 2}

\frac{3 ( s + 2 )}{( s + 1 ) ( s + 3 )}

What is expand ((y-2)dy)/((y-3)(y-1)) ?
The solution to expand ((y-2)dy)/((y-3)(y-1)) is (ydy-2dy)/(y^2-4y+3)