What is expand (-(-1)^{x-1}-15+4x)/2 ?

The solution to expand (-(-1)^{x-1}-15+4x)/2 is -((-1)^{x-1})/2-15/2+2x

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expand (-(-1)^{x-1}-15+4x)/2

expand

\frac{- ( - 1 ) ^{x - 1} - 15 + 4 x}{2}

- \frac{( - 1 ) ^{x - 1}}{2} - \frac{15}{2} + 2 x

Solution steps

\frac{- ( - 1 ) ^{x - 1} - 15 + 4 x}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- ( - 1 ) ^{x - 1} - 15 + 4 x}{2} = - \frac{( - 1 ) ^{x - 1}}{2} - \frac{15}{2} + \frac{4 x}{2}

= - \frac{( - 1 ) ^{x - 1}}{2} - \frac{15}{2} + \frac{4 x}{2}

Divide the numbers:

\frac{4}{2} = 2

= - \frac{( - 1 ) ^{x - 1}}{2} - \frac{15}{2} + 2 x

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What is expand (-(-1)^{x-1}-15+4x)/2 ?
The solution to expand (-(-1)^{x-1}-15+4x)/2 is -((-1)^{x-1})/2-15/2+2x