What is expand e^{4t}(t-4)^2 ?

The solution to expand e^{4t}(t-4)^2 is e^{4t}t^2-8e^{4t}t+16e^{4t}

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expand e^{4t}(t-4)^2

expand

e^{4 t} (t - 4)^{2}

e^{4 t} t^{2} - 8 e^{4 t} t + 16 e^{4 t}

Solution steps

e^{4 t} (t - 4)^{2}

(t - 4)^{2} = t^{2} - 8 t + 16

= e^{4 t} (t^{2} - 8 t + 16)

Distribute parentheses

= e^{4 t} t^{2} + e^{4 t} (- 8 t) + e^{4 t} \cdot 16

Apply minus-plus rules

+ (- a) = - a

= e^{4 t} t^{2} - 8 e^{4 t} t + 16 e^{4 t}

\frac{3 ( 2 + 1 )}{2}

\frac{d}{d p} ((x (p)) (20 (15 - p)))

(1 - t (x)) \cdot x^{'}

8 n - (6 n + 5 = 9)

(c x^{2} + b x + a) (f x^{2} + e x + d)

What is expand e^{4t}(t-4)^2 ?
The solution to expand e^{4t}(t-4)^2 is e^{4t}t^2-8e^{4t}t+16e^{4t}