What is expand (e^xx-e^x+5-2e)(2x-1) ?

The solution to expand (e^xx-e^x+5-2e)(2x-1) is 2e^xx^2-3e^xx+e^x+10x-5-4ex+2e

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expand (e^xx-e^x+5-2e)(2x-1)

expand

(e^{x} x - e^{x} + 5 - 2 e) (2 x - 1)

2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 10 x - 5 - 4 e x + 2 e

Solution steps

(e^{x} x - e^{x} + 5 - 2 e) (2 x - 1)

Distribute parentheses

= e^{x} x \cdot 2 x + e^{x} x (- 1) + (- e^{x}) \cdot 2 x + (- e^{x}) (- 1) + 5 \cdot 2 x + 5 (- 1) + (- 2 e) \cdot 2 x + (- 2 e) (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 e^{x} xx - 1 \cdot e^{x} x - 2 e^{x} x + 1 \cdot e^{x} + 5 \cdot 2 x - 5 \cdot 1 - 2 \cdot 2 e x + 2 \cdot 1 e

Simplify

2 e^{x} xx - 1 \cdot e^{x} x - 2 e^{x} x + 1 \cdot e^{x} + 5 \cdot 2 x - 5 \cdot 1 - 2 \cdot 2 e x + 2 \cdot 1 e : 2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 10 x - 5 - 4 e x + 2 e

= 2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 10 x - 5 - 4 e x + 2 e

V ECTORES (2, - 3) (4, 6)

\frac{x ( x ^{2} - x )}{x + 1}

x + 5^{2}

(1 + x + 3 x^{2})^{6}

\frac{y ^{2} ( 2 x - 6 y )}{6 x y ^{2} + 1}

What is expand (e^xx-e^x+5-2e)(2x-1) ?
The solution to expand (e^xx-e^x+5-2e)(2x-1) is 2e^xx^2-3e^xx+e^x+10x-5-4ex+2e