What is expand 1/(2(x-2)(2x-3)(4x+7)) ?

The solution to expand 1/(2(x-2)(2x-3)(4x+7)) is 1/(16x^3-28x^2-50x+84)

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expand 1/(2(x-2)(2x-3)(4x+7))

expand

\frac{1}{2 ( x - 2 ) ( 2 x - 3 ) ( 4 x + 7 )}

\frac{1}{16 x ^{3} - 28 x ^{2} - 50 x + 84}

Solution steps

\frac{1}{2 ( x - 2 ) ( 2 x - 3 ) ( 4 x + 7 )}

Expand

2 (x - 2) (2 x - 3) (4 x + 7) : 16 x^{3} - 28 x^{2} - 50 x + 84

= \frac{1}{16 x ^{3} - 28 x ^{2} - 50 x + 84}

\frac{( 2 + θ ) ^{2}}{2}

\frac{d y}{x} (x^{2} + 16 y^{2} = 25)

(- 6 x - 7 y = 14) \cdot 3

\frac{( c b + d a ) ( c + d )}{ba}

What is expand 1/(2(x-2)(2x-3)(4x+7)) ?
The solution to expand 1/(2(x-2)(2x-3)(4x+7)) is 1/(16x^3-28x^2-50x+84)