What is expand ((3s+4)^3)/9 ?

The solution to expand ((3s+4)^3)/9 is 3s^3+12s^2+16s+64/9

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expand ((3s+4)^3)/9

expand

\frac{( 3 s + 4 ) ^{3}}{9}

3 s^{3} + 12 s^{2} + 16 s + \frac{64}{9}

Solution steps

\frac{( 3 s + 4 ) ^{3}}{9}

(3 s + 4)^{3} = 27 s^{3} + 108 s^{2} + 144 s + 64

= \frac{27 s ^{3} + 108 s ^{2} + 144 s + 64}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 s ^{3} + 108 s ^{2} + 144 s + 64}{9} = \frac{27 s ^{3}}{9} + \frac{108 s ^{2}}{9} + \frac{144 s}{9} + \frac{64}{9}

= \frac{27 s ^{3}}{9} + \frac{108 s ^{2}}{9} + \frac{144 s}{9} + \frac{64}{9}

Divide the numbers:

\frac{27}{9} = 3

= 3 s^{3} + \frac{108 s ^{2}}{9} + \frac{144 s}{9} + \frac{64}{9}

Divide the numbers:

\frac{108}{9} = 12

= 3 s^{3} + 12 s^{2} + \frac{144 s}{9} + \frac{64}{9}

Divide the numbers:

\frac{144}{9} = 16

= 3 s^{3} + 12 s^{2} + 16 s + \frac{64}{9}

\frac{2 - x ( x + 2 + 2 )}{x - 2}

\frac{19 x + 2}{2 ( 4 x ^{2} - 6 x + 8 )}

\frac{3 ( 13 + 2 13 )}{13}

- 2 (x + 2 = - 2 x + 1)

(x - 3) \circ (x + 5)

What is expand ((3s+4)^3)/9 ?
The solution to expand ((3s+4)^3)/9 is 3s^3+12s^2+16s+64/9