What is expand (e^xx-e^x+C)(2x-1) ?

The solution to expand (e^xx-e^x+C)(2x-1) is 2e^xx^2-3e^xx+e^x+2xC-C

Popular >

expand (e^xx-e^x+C)(2x-1)

expand

(e^{x} x - e^{x} + C) (2 x - 1)

2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 2 x C - C

Solution steps

(e^{x} x - e^{x} + C) (2 x - 1)

Distribute parentheses

= e^{x} x \cdot 2 x + e^{x} x (- 1) + (- e^{x}) \cdot 2 x + (- e^{x}) (- 1) + C \cdot 2 x + C (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 e^{x} xx - 1 \cdot e^{x} x - 2 e^{x} x + 1 \cdot e^{x} + 2 x C - 1 \cdot C

Simplify

2 e^{x} xx - 1 \cdot e^{x} x - 2 e^{x} x + 1 \cdot e^{x} + 2 x C - 1 \cdot C : 2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 2 x C - C

= 2 e^{x} x^{2} - 3 e^{x} x + e^{x} + 2 x C - C

(2 x - e^{x}) \cdot (e^{- x} + 1)

\frac{45 a}{( x + 2.9 ) ( x + 0.14 )}

\frac{( x + 1 ) ( x - 1 )}{2 x ( 2 x + 1 )}

(m^{2} - n^{2})^{2} + 2 mn

\frac{( - 1 - 2 x ) ( 3 - 2 x ^{2} )}{3}

What is expand (e^xx-e^x+C)(2x-1) ?
The solution to expand (e^xx-e^x+C)(2x-1) is 2e^xx^2-3e^xx+e^x+2xC-C