What is expand solve(2x^2+9x-5=0) ?

The solution to expand solve(2x^2+9x-5=0) is 2elsovx^2+9elsovx-5elsov=0

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expand solve(2x^2+9x-5=0)

expand

so l v e (2 x^{2} + 9 x - 5 = 0)

2 e l so v x^{2} + 9 e l so vx - 5 e l so v = 0

Solution steps

so l v e (2 x^{2} + 9 x - 5 = 0)

= e l so v (2 x^{2} + 9 x - 5 \cdot 0 =)

Distribute parentheses

= so l v e 2 x^{2} + so l v e 9 x + so l v e (- 5 = 0)

Apply minus-plus rules

+ (- a) = - a

2 e l so v x^{2} + 9 e l so vx - 5 e l so v = 0

\frac{9 x ^{3}}{( x - 6 ) ^{2}}

\frac{3 ( x + 1 )}{x [ 2 ]}

5 - (9 x + 5 = 3 - x)

(a + b) (c + d) (e + f) (g + h)

k (p = 4 k + 4 u (p))

What is expand solve(2x^2+9x-5=0) ?
The solution to expand solve(2x^2+9x-5=0) is 2elsovx^2+9elsovx-5elsov=0