What is expand-2(2x-1=17-4x) ?

The solution to expand-2(2x-1=17-4x) is -4x+2=17+8x

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expand-2(2x-1=17-4x)

expand

- 2 (2 x - 1 = 17 - 4 x)

- 4 x + 2 = 17 + 8 x

Solution steps

- 2 (2 x - 1 = 17 - 4 x)

= - 2 (2 x - 1 \cdot 17 = - 4 x)

Distribute parentheses

= (- 2) \cdot 2 x + (- 2) (- 1 = 17) + (- 2) (- 4 x)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 2 \cdot 2 x + 2 \cdot 1 = 17 + 2 \cdot 4 x

Simplify

- 2 \cdot 2 x + 2 \cdot 1 = 17 + 2 \cdot 4 x : - 4 x + 2 = 17 + 8 x

- 4 x + 2 = 17 + 8 x

\frac{x + 4}{x ^{2} ( x ^{2} + 4 )}

- \frac{3 ( 2 - 11 )}{7}

\frac{d}{d y} ((x) (84 x - x^{2}))

\frac{x}{( ( x - 2 ) ( x - 1 ) ^{3} )}

\frac{( - 1 ) ^{n + 1} ( n - 1 ) ( n + 2 )}{n}

What is expand-2(2x-1=17-4x) ?
The solution to expand-2(2x-1=17-4x) is -4x+2=17+8x