What is expand ((3x+12y)(3x+28y))/(16) ?

The solution to expand ((3x+12y)(3x+28y))/(16) is (9x^2}{16}+\frac{15xy)/2+21y^2

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expand ((3x+12y)(3x+28y))/(16)

expand

\frac{( 3 x + 12 y ) ( 3 x + 28 y )}{16}

\frac{9 x ^{2}}{16} + \frac{15 x y}{2} + 21 y^{2}

Solution steps

\frac{( 3 x + 12 y ) ( 3 x + 28 y )}{16}

Expand

(3 x + 12 y) (3 x + 28 y) : 9 x^{2} + 120 x y + 336 y^{2}

= \frac{9 x ^{2} + 120 x y + 336 y ^{2}}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} + 120 x y + 336 y ^{2}}{16} = \frac{9 x ^{2}}{16} + \frac{120 x y}{16} + \frac{336 y ^{2}}{16}

= \frac{9 x ^{2}}{16} + \frac{120 x y}{16} + \frac{336 y ^{2}}{16}

Cancel

\frac{120 x y}{16} : \frac{15 x y}{2}

= \frac{9 x ^{2}}{16} + \frac{15 x y}{2} + \frac{336 y ^{2}}{16}

Divide the numbers:

\frac{336}{16} = 21

= \frac{9 x ^{2}}{16} + \frac{15 x y}{2} + 21 y^{2}

e^{y} (- e^{- y} y - e^{- y})

\frac{i wl}{R ( 1 - w ^{2} l c ) + i wl}

f^{(4)} 6 (6 ln (5 x) + 11)

sin^{2} (x) sin^{2} (x)

x^{q (1 - q)}

What is expand ((3x+12y)(3x+28y))/(16) ?
The solution to expand ((3x+12y)(3x+28y))/(16) is (9x^2}{16}+\frac{15xy)/2+21y^2