What is expand-6*(5e^{-2x}+7e^{3x}) ?

The solution to expand-6*(5e^{-2x}+7e^{3x}) is -30e^{-2x}-42e^{3x}

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expand-6*(5e^{-2x}+7e^{3x})

expand

- 6 \cdot (5 e^{- 2 x} + 7 e^{3 x})

- 30 e^{- 2 x} - 42 e^{3 x}

Solution steps

- 6 (5 e^{- 2 x} + 7 e^{3 x})

Apply the distributive law:

a (b + c) = ab + a c

a = - 6, b = 5 e^{- 2 x}, c = 7 e^{3 x}

= - 6 \cdot 5 e^{- 2 x} + (- 6) \cdot 7 e^{3 x}

Apply minus-plus rules

+ (- a) = - a

= - 6 \cdot 5 e^{- 2 x} - 6 \cdot 7 e^{3 x}

Simplify

- 6 \cdot 5 e^{- 2 x} - 6 \cdot 7 e^{3 x} : - 30 e^{- 2 x} - 42 e^{3 x}

= - 30 e^{- 2 x} - 42 e^{3 x}

(a e^{x} + a e^{- x} + a e^{2 x} + 3)^{3}

26 e^{- 13 x} + 13 (2 - 2 e^{- 13 x}) - 26

\frac{d x}{( 25 x ^{2} + 9 ) s}

\frac{40 ( 2 15 - 3 )}{17}

\frac{b}{s ^{2} ( s + 1 )}

What is expand-6*(5e^{-2x}+7e^{3x}) ?
The solution to expand-6*(5e^{-2x}+7e^{3x}) is -30e^{-2x}-42e^{3x}