What are the solutions to the equation u^2+u-2=0 ?

The solutions to the equation u^2+u-2=0 are u=1,u=-2

Find the zeros of u^2+u-2=0

The zeros of u^2+u-2=0 are u=1,u=-2

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u^{2} + u - 2 = 0

u = 1, u = - 2

Solution steps

u^{2} + u - 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

u_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 1 + 3}{2 \cdot 1}, u_{2} = \frac{- 1 - 3}{2 \cdot 1}

u = \frac{- 1 + 3}{2 \cdot 1} : 1

u = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

u = 1, u = - 2

\frac{3 ^{4}}{3 ^{8}}

5903 = P + P (6.4) (5)

∣ - 3 x - 2 ∣ = 5

\frac{130 0 ^{3}}{4.082 + 0.6}

∣ 5 - 2 x ∣ > 7

What are the solutions to the equation u^2+u-2=0 ?
The solutions to the equation u^2+u-2=0 are u=1,u=-2
Find the zeros of u^2+u-2=0
The zeros of u^2+u-2=0 are u=1,u=-2