What is expand ((5-2x)^2)/pi-x^2 ?

The solution to expand ((5-2x)^2)/pi-x^2 is (25)/pi-(20x)/pi+(4x^2)/pi-x^2

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expand ((5-2x)^2)/pi-x^2

expand

\frac{( 5 - 2 x ) ^{2}}{π} - x^{2}

\frac{25}{π} - \frac{20 x}{π} + \frac{4 x ^{2}}{π} - x^{2}

Solution steps

\frac{( 5 - 2 x ) ^{2}}{π} - x^{2}

(5 - 2 x)^{2} = 25 - 20 x + 4 x^{2}

= \frac{4 x ^{2} - 20 x + 25}{π} - x^{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{25 - 20 x + 4 x ^{2}}{π} = \frac{25}{π} - \frac{20 x}{π} + \frac{4 x ^{2}}{π}

= \frac{25}{π} - \frac{20 x}{π} + \frac{4 x ^{2}}{π} - x^{2}

(l, m, n) (1, - 4, - 2)

5^{3} \cdot 8^{4}

\frac{x ^{2} - 9 x - 48}{( x + 6 ) ( x - 1 )}

30 (a + b + c + d + e + f)

\frac{x ^{3}}{( 1 + x ^{4} ) ^{2}}

What is expand ((5-2x)^2)/pi-x^2 ?
The solution to expand ((5-2x)^2)/pi-x^2 is (25)/pi-(20x)/pi+(4x^2)/pi-x^2