What is expand 0.5t+0.12(t+1=5.7) ?

The solution to expand 0.5t+0.12(t+1=5.7) is 0.62t+0.12=5.7

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expand 0.5t+0.12(t+1=5.7)

expand

0.5 t + 0.12 (t + 1 = 5.7)

0.62 t + 0.12 = 5.7

Solution steps

0.5 t + 0.12 (t + 1 = 5.7)

= 0.5 t + 0.12 (t + 1 \cdot 5.7 =)

Expand

0.12 (t + 1 = 5.7) : 0.12 t + 0.12 = 5.7

0.5 t + 0.12 t + 0.12 = 5.7

Expand

0.5 t + 0.12 t + 0.12 : 0.62 t + 0.12

0.62 t + 0.12 = 5.7

(5 - 2 e^{4 x})^{2}

100 + e^{((x + 30) \cdot 0.1)}

\frac{( x + 1 ) ( x + 2 )}{( x + 11 ) ( x - 2 )}

(- \frac{t}{100 π} + K)^{2}

lo g_{2} (b)

What is expand 0.5t+0.12(t+1=5.7) ?
The solution to expand 0.5t+0.12(t+1=5.7) is 0.62t+0.12=5.7