What is expand (1,i)(2-1,3+2i) ?

The solution to expand (1,i)(2-1,3+2i) is 2(1i,)-1*(1i,),3+2i(1i,)

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expand (1,i)(2-1,3+2i)

expand

(1, i) (2 - 1, 3 + 2 i)

2 (1 i,) - 1 \cdot (1 i,), 3 + 2 i (1 i,)

Solution steps

(1, i) (2 - 1, 3 + 2 i)

= (1 i,) (2 - 1 \cdot 3, + 2 i)

Distribute parentheses

= (1, i) \cdot 2 + (1, i) (- 1, 3) + (1, i) \cdot 2 i

Apply minus-plus rules

+ (- a) = - a

= 2 (1 i,) - 1 \cdot (1 i,), 3 + 2 i (1 i,)

\frac{( x + 3 ) ( 3 x + 1 + 1 )}{3}

e^{x} (x^{3} - 3 x)

\frac{1}{x ( a - b ln ( x ) )}

9 (e^{x} + cos (3 x) + sin (3 x))

(n + 1)! (n + 2) - 1

What is expand (1,i)(2-1,3+2i) ?
The solution to expand (1,i)(2-1,3+2i) is 2(1i,)-1*(1i,),3+2i(1i,)