What is expand-((-1)^n-1)/(n^2) ?

The solution to expand-((-1)^n-1)/(n^2) is -((-1)^n)/(n^2)+1/(n^2)

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expand-((-1)^n-1)/(n^2)

expand

- \frac{( - 1 ) ^{n} - 1}{n ^{2}}

- \frac{( - 1 ) ^{n}}{n ^{2}} + \frac{1}{n ^{2}}

Solution steps

- \frac{( - 1 ) ^{n} - 1}{n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( - 1 ) ^{n} - 1}{n ^{2}} = - (\frac{( - 1 ) ^{n}}{n ^{2}}) - (- \frac{1}{n ^{2}})

= - (\frac{( - 1 ) ^{n}}{n ^{2}}) - (- \frac{1}{n ^{2}})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{( - 1 ) ^{n}}{n ^{2}} + \frac{1}{n ^{2}}

5 (311)

(e^{x} + e^{- x})^{3}

3^{12}

\frac{25 ( 69 - 4313 )}{4}

3 x + 5 x

What is expand-((-1)^n-1)/(n^2) ?
The solution to expand-((-1)^n-1)/(n^2) is -((-1)^n)/(n^2)+1/(n^2)